# Aptitude  Number series  Practice Q&A

1. If $n$ is a natural number, then 6n2 + 6n is always divisible by:

 6 only 6 and 12 both 12 only by 18 only

2. 107 x 107 + 93 x 93 = ?

 19578 19418 20098 21908

3. What will be remainder when (6767 + 67) is divided by 68 ?

 1 63 66 67

4. On dividing a number by 5, we get 3 as remainder. What will the remainder when the square of the this number is divided by 5 ?

 0 1 2 4

5. How many 3-digit numbers are completely divisible 6 ?

 149 150 151 166

6. How many natural numbers are there between 23 and 100 which are exactly divisible by 6 ?

 8 11 12 13

7. How many of the following numbers are divisible by 3 but not by 9 ?
2133, 2343, 3474, 4131, 5286, 5340, 6336, 7347, 8115, 9276

 5 6 7 None of these

8. $\dfrac{(963 + 476)^2 + (963 - 476)^2}{(963 \times 963 + 476 \times 476)}$=?

 1449 497 2 4

9. How many 3 digit numbers are divisible by 6 in all ?

 149 150 151 166

10. A 3-digit number 4a3 is added to another 3-digit number 984 to give a 4-digit number 13b7, which is divisible by 11. Then, (a +b) = ?

 10 11 12 15