669.The present average age of a couple and their daughter is 35 years. Fifteen years from now, the age of the mother will be equal to the sum of present ages of the father and the daughter. Find the present age of mother?
43 years
40 years
48 years
45 years
Explanation:
let the sum of the daughter's and the father's age be 'x'
let the mother's age be 'y'
therefore their average age = x+y= 35
therefore, x + y= 105 ----(1)
now, 15+y=x
therefore x-y = 15-----------(2)
adding 2 and 1 we get
so, x+y=105
x-y =15
__________________
2x=120
therefore x=60
putting x=60 in equation (1)when we get,
y=105-60
y=45
so the Ans is 45
let the sum of the daughter's and the father's age be 'x'
let the mother's age be 'y'
therefore their average age = x+y= 35
therefore, x + y= 105 ----(1)
now, 15+y=x
therefore x-y = 15-----------(2)
adding 2 and 1 we get
so, x+y=105
x-y =15
__________________
2x=120
therefore x=60
putting x=60 in equation (1)when we get,
y=105-60
y=45
so the Ans is 45
1221.Four years ago, the average age of A and B was 18 years. At present the average age of A, B and C is 24 years. What would be the age of C after 8 years?
36 years
32 years
28 years
25 years
Explanation:
Sum of the present ages of A and B
= (18 × 2 + 4 × 2) years
= 44 years
Sum of the present ages of A, B and C
= (24 × 3) years
= 72 years
C's present age
= (72 - 44) years
= 28 years
∴ C's age after 8 years
= (28 + 8) years
= 36 years
Sum of the present ages of A and B
= (18 × 2 + 4 × 2) years
= 44 years
Sum of the present ages of A, B and C
= (24 × 3) years
= 72 years
C's present age
= (72 - 44) years
= 28 years
∴ C's age after 8 years
= (28 + 8) years
= 36 years
1293.The total age of A and B is
12
years more than the total age of B and C. C is younger than A by:
11 years
13 years
10
12
Explanation:
Total age of A and B is 12 years more than total age of B and C.
Since B is common in both sides, we can rephrase the statement as
"age of A is 12 years more than age of C".
That is, C is 12 years younger than A.
Total age of A and B is 12 years more than total age of B and C.
Since B is common in both sides, we can rephrase the statement as
"age of A is 12 years more than age of C".
That is, C is 12 years younger than A.
1294.Raju is as much younger than Sonu as he is older than Tanu. If the sum of the ages of Sonu and Tanu is 50 years, what is definitely the difference between Sonu and Raju's age?
13
15
45
cannot be determined
Explanation:
Let,
Raju =Q
Sonu =R
Tanu =T
Given that:
1. The difference of age b/w R and Q = The difference of age b/w Q and T.
2. Sum of age of R and T is 50 i.e. (R + T) = 50.
Question: R - Q = ?.
Explanation:
R - Q = Q - T
(R + T) = 2Q
Now given that, (R + T) = 50
So, 50 = 2Q and therefore Q = 25.
Question is (R - Q) = ?
Here we know the value(age) of Q (25), but we don't know the age of R.
Therefore, (R-Q) cannot be determined.
Let,
Raju =Q
Sonu =R
Tanu =T
Given that:
1. The difference of age b/w R and Q = The difference of age b/w Q and T.
2. Sum of age of R and T is 50 i.e. (R + T) = 50.
Question: R - Q = ?.
Explanation:
R - Q = Q - T
(R + T) = 2Q
Now given that, (R + T) = 50
So, 50 = 2Q and therefore Q = 25.
Question is (R - Q) = ?
Here we know the value(age) of Q (25), but we don't know the age of R.
Therefore, (R-Q) cannot be determined.
1295.Soniya got married 7 years ago. Her present age is 6/5 times her age at the time of marriage. Her brother was 5 years younger to her at the time of marriage. What is the age of her brother at present?
Cant be determined
55
35
36
1296.Mother is aged 3 times more than her son Sanjay. After 12 years she would be 2 and a half times of Sanjays age. After further 12 years how many times would she be Sanjays age?
37
38
1
2
1297.A mother said to her son, “I was as old as you are at present at the time of your birth.” If the mothers age is 36 years now the sons age 6 years back will be how many years?
12
4
11.5
12.5
Explanation:
Let, the mother's present age be M and his son's present age be S.
Given, when his son was born, she was the same age as her son. Now since the son's age is S, he would be born S years ago.
Hence, mother's age S years ago = M - S.
But her, age was same as the present age of son.
→ M - S = S
→ M = 2S
Now, we know her present age is 36. So,
36 = 2S
→ S = 36/2
→ S = 18 years.
Son's present age is 18 years. Hence, his age 6 years back would be 12 years.
Let, the mother's present age be M and his son's present age be S.
Given, when his son was born, she was the same age as her son. Now since the son's age is S, he would be born S years ago.
Hence, mother's age S years ago = M - S.
But her, age was same as the present age of son.
→ M - S = S
→ M = 2S
Now, we know her present age is 36. So,
36 = 2S
→ S = 36/2
→ S = 18 years.
Son's present age is 18 years. Hence, his age 6 years back would be 12 years.
1298.The age of Rajeev is 1/6th of his mothers present age. Rajeevs mother age will be twice of his sister Kamalas age after 10 years. If Kamalas 8th birthday was celebrated two years before, then what is Rajeevs present age?
13.5
14.5
5
4
Explanation:
Let the present age of father be a
Present age of Rajeev= a/6
According to first condition,
( a + 10) = 2 ( Kamal's present age + 10)
=> (a + 10) /2 - 10 = Kamal's present age
=> Kamal's present age = ( a + 10 - 20) / 2
=> Kamal's present age = ( a - 10) /2
Now,
According to second condition,
( a - 10)/2 - 2 = 8
=> ( a - 10 - 4) / 2 = 8
=> a - 14 = 16
=> a = 30
Rajeev's present age = 30 /6 = 5 years
Let the present age of father be a
Present age of Rajeev= a/6
According to first condition,
( a + 10) = 2 ( Kamal's present age + 10)
=> (a + 10) /2 - 10 = Kamal's present age
=> Kamal's present age = ( a + 10 - 20) / 2
=> Kamal's present age = ( a - 10) /2
Now,
According to second condition,
( a - 10)/2 - 2 = 8
=> ( a - 10 - 4) / 2 = 8
=> a - 14 = 16
=> a = 30
Rajeev's present age = 30 /6 = 5 years
1299.Sindus was asked about her age in years. Her reply was, “Take my age 3 years hence, multiply it by 3 and then minus 3 times. Here age of mine 3 years ago and you will come to know how old I am”. What was the age of Sindhu?
12
9
12
18
Explanation:
Lets assume her current age is ‘x’.
Her age 3 years from now: (x+3)
Her age 3 years earlier: (x-3).
As per what is stated, her current age is - 3(x+3) - 3(x-3)
Therefore, solve x= 3x + 9 - 3x + 9
The answer is x = 18
Lets assume her current age is ‘x’.
Her age 3 years from now: (x+3)
Her age 3 years earlier: (x-3).
As per what is stated, her current age is - 3(x+3) - 3(x-3)
Therefore, solve x= 3x + 9 - 3x + 9
The answer is x = 18
1300.If Priya was 1/3rd as old as Peter 5 years back and Priya is 17 years old now, How old is Peter now?
19
20
41
51
Explanation:
Priya’s age today = 17 years
Hence, 5 years back, he must be 12 years old.
Peter must be 36 years old, Because (3×12).
5 years back Peter must be 41 years old today. Because (36+5)=41
Priya’s age today = 17 years
Hence, 5 years back, he must be 12 years old.
Peter must be 36 years old, Because (3×12).
5 years back Peter must be 41 years old today. Because (36+5)=41
1301.12 years from now Tanu will be twice as old as Manu. The current sum of the ages of Tanu and Manu is 57. How old is Manu right now?
42
43
15
18
1302.The age of a person is thrice the total ages of his 2 daughters. 0.5 decades hence, his age will be twice of the total ages of his daughters. Then what is the fathers current age?
[0.5 Decades = 5 Years]
[0.5 Decades = 5 Years]
45 years
25 years
35 years
38 years
Explanation:
Let, Total of current ages of the 2 daughters is A years.
Then, father’s current age = 3A years.
(3A + 5) = 2 (A +10)
3A + 5 = 2A + 20
A = 15
Therefore, father’s current age = 45 years.
Let, Total of current ages of the 2 daughters is A years.
Then, father’s current age = 3A years.
(3A + 5) = 2 (A +10)
3A + 5 = 2A + 20
A = 15
Therefore, father’s current age = 45 years.
1303.Sivagami is 2 years elder than Meena. After 6 years the total of their ages will be 7 times of their current age. Then age of Sivagami is :
5 years
4 years
2 Years
7 years
Explanation:
Suppose Sivagami present age as x
therefore Meena’s present age = x-2;
present total = x+x-2 = 2x-2
After 6 years,
Shivagami’s age =x+6
Meena’s age = x-2+6=x+4
sum = x+6+x+4 = 2x +10
According to question ,
2x+10 = 7(2x-2)
2x+10 = 14x-14
12x=24
x=2 age of Sivagami is 2
Suppose Sivagami present age as x
therefore Meena’s present age = x-2;
present total = x+x-2 = 2x-2
After 6 years,
Shivagami’s age =x+6
Meena’s age = x-2+6=x+4
sum = x+6+x+4 = 2x +10
According to question ,
2x+10 = 7(2x-2)
2x+10 = 14x-14
12x=24
x=2 age of Sivagami is 2
1304.Pandey got married 0.8 decades ago. His current age is (6/5) times his age at the time of his marriage. Pandeys brother was ten years younger to him at the time of his marriage. What is the age of Pandeys Brother?[0.8 decades = 8 years]
21 years
Data inadequate
38 years
39 years
Explanation:
Let Rajan’s present age be x years. Then, his age at the time of marriage = (x – 8) years
x = 6/5 (x - 8)
5x = 6x - 48
x = 48
Rajan’s sister’s age at the time of his marriage = (x – 8) – 10 = (x – 18) = 30 years.
Rajan's sister's present age = (30 + 8) years = 38 years
Let Rajan’s present age be x years. Then, his age at the time of marriage = (x – 8) years
x = 6/5 (x - 8)
5x = 6x - 48
x = 48
Rajan’s sister’s age at the time of his marriage = (x – 8) – 10 = (x – 18) = 30 years.
Rajan's sister's present age = (30 + 8) years = 38 years
1305.The ages of a man and his son is in the ratio of 7: 2. After 15 years, they would be in the ratio of 2 : 1, what was father's age when son was born ?
25 years
58 years
20 years
22 years
Explanation:
Let father age is 7x
And son age is 2x
then after 15 year father age is 7x+15
After 15 year son age is 2x+15
⇒ $\dfrac{7x+15}{2x+15}=\dfrac{2}{1} $ ⇒4x+30=7x+15
⇒4x−7x=15−30
⇒−3x=−15⇒x=5
Hence father present age=7×5=35
Son present age=2×5=10
difference of father and son age=35−10=25
So father age was 25 years when son was born
Let father age is 7x
And son age is 2x
then after 15 year father age is 7x+15
After 15 year son age is 2x+15
⇒ $\dfrac{7x+15}{2x+15}=\dfrac{2}{1} $ ⇒4x+30=7x+15
⇒4x−7x=15−30
⇒−3x=−15⇒x=5
Hence father present age=7×5=35
Son present age=2×5=10
difference of father and son age=35−10=25
So father age was 25 years when son was born
1306.Mother is aged thrice than her daughter Rani. After 8 years, he would be 2(1/2) times of Ranis age. After 8 years, how many times would she be of Ranis age?
18 times
16 times
2(1/2) times
2 times
Explanation:
Let Rani age is 'x' years.so his mother's age is 3x. after 8 years,
Therefore,Rani age is 'x+8' his mother's age is 2 and half times Rani age
so,3x+8=5/2(x+8)
..x=24 mother's age =3(24)=72
After 8 years Rani age=32 and mother's age is 80
again after 8 years Rani age=40 and mother's age is 88
Therefore mother's age is 2.2 times of Rani age.
Let Rani age is 'x' years.so his mother's age is 3x. after 8 years,
Therefore,Rani age is 'x+8' his mother's age is 2 and half times Rani age
so,3x+8=5/2(x+8)
..x=24 mother's age =3(24)=72
After 8 years Rani age=32 and mother's age is 80
again after 8 years Rani age=40 and mother's age is 88
Therefore mother's age is 2.2 times of Rani age.
1307. The ages of Rahul and Karan are in the ratio 7:5. Ten years hence, the ratios of their ages will be 9:7. Find Rahul present age?
25 years
45 years
24 years
35 years
Explanation:
Let Rahul's and Karan's age be 7x and 5x respectively.
After 10 yrs, their ages are 7x + 10, 5x + 10 respectively.
As per the given condition, Ratio after 10 years is 9:7
So, $\dfrac{7x+10}{5x+10}=\dfrac{9}{7}$
Cross Multiplying, we get
7(7x + 10) = 9(5x + 10)
49x + 70 = 45x + 90
49x - 45x = 90 - 70
4x = 20
x = 5
Therefore,
Rahul's age = 7 × 5 = 35 years
Let Rahul's and Karan's age be 7x and 5x respectively.
After 10 yrs, their ages are 7x + 10, 5x + 10 respectively.
As per the given condition, Ratio after 10 years is 9:7
So, $\dfrac{7x+10}{5x+10}=\dfrac{9}{7}$
Cross Multiplying, we get
7(7x + 10) = 9(5x + 10)
49x + 70 = 45x + 90
49x - 45x = 90 - 70
4x = 20
x = 5
Therefore,
Rahul's age = 7 × 5 = 35 years
1308.A year ago the proportion between Sham and Amirs age was 4:3. 1 year hence the proportion of their ages will be 5:4. The total of their current ages is :
28
16
13
14
Explanation:
Let the present age of Sham be X.
Let the present age of Amir be Y.
=> Age of Sham one year back = X-1.
=> Age of Amir one year back = Y-1.
And, Age of Sham after one year = X+1.
And, Age of Amir after one year = Y+1.
Ratio of Sham's and Amir's ages one year back = 4:3.
=> X-1/Y-1 = 4/3
3X-3 = 4Y-4
3X-4Y= -1 -------------> 1
Ratio of Sham's and Amir's ages after one year = 5:4.
=> X+1/Y+1 = 5/4
4X+4 = 5Y+5
4X-5Y = 1 -----------------> 2
Solving 1 and 2, we get
X=9 and Y=7.
The sum of their ages is 16
Let the present age of Sham be X.
Let the present age of Amir be Y.
=> Age of Sham one year back = X-1.
=> Age of Amir one year back = Y-1.
And, Age of Sham after one year = X+1.
And, Age of Amir after one year = Y+1.
Ratio of Sham's and Amir's ages one year back = 4:3.
=> X-1/Y-1 = 4/3
3X-3 = 4Y-4
3X-4Y= -1 -------------> 1
Ratio of Sham's and Amir's ages after one year = 5:4.
=> X+1/Y+1 = 5/4
4X+4 = 5Y+5
4X-5Y = 1 -----------------> 2
Solving 1 and 2, we get
X=9 and Y=7.
The sum of their ages is 16
1309.A mother said to her daughter, “I was as old as you are at now at the date of your birth.” If the mothers age is 38 years now, the daughters age 5 years back was?
16 years
None of these
14 years
19 years
Explanation:
Daughter’s current age = A
(38 – A) = A
2A = 38
A = 19 years
Daughter’s age Five years back = 19 – 5 = 14 years
Daughter’s current age = A
(38 – A) = A
2A = 38
A = 19 years
Daughter’s age Five years back = 19 – 5 = 14 years
1310.Proportion of Yuvarajs age to Gangulys age is 4:3. Yuvaraj willl be 26 years old after 6 years. What is the age of Ganguly now?
23 years
29 years
17 years
15 years
Explanation:
Current ages of Yuvaraj = 4A and Ganguly = 3A
So that 4A + 6 = 26
A = 5
Current age of Ganguly = 3A
=> 3 x 5 = 15 years
Current ages of Yuvaraj = 4A and Ganguly = 3A
So that 4A + 6 = 26
A = 5
Current age of Ganguly = 3A
=> 3 x 5 = 15 years