1256.A train 575 m long crosses a tunnel of length 325 in 90 sec. What is the speed of the train in kmph
34 kmph
35 kmph
28 kmph
36 kmph
Explanation:
Total distance traveled = Length of train + Length of tunnel = 575 + 325 = 900
Time taken to cross the tunnel = 90 sec.
Speed in kmph = distance/time *18/5
= 900/90 * 18/5
= 180/5
= 36 kmph
Total distance traveled = Length of train + Length of tunnel = 575 + 325 = 900
Time taken to cross the tunnel = 90 sec.
Speed in kmph = distance/time *18/5
= 900/90 * 18/5
= 180/5
= 36 kmph
1257.A train which has 390 m long, is running 45 kmph. In what time will it cross a person moving at 9 kmph in same direction ?
36
24 sec
26 sec
39 sec
Explanation:
Time taken to cross a moving person = length of train/ relative speed
Time taken = 390/((45-9) (5/18)
= 390/ 36*(5/18)
= 390/10
= 39 sec
Time taken to cross a moving person = length of train/ relative speed
Time taken = 390/((45-9) (5/18)
= 390/ 36*(5/18)
= 390/10
= 39 sec
1258.Two persons start running simultaneously around a circular track of length 400 m from the same point at speeds of 15 kmph and 25 kmph. When will they meet for the first time any where on the track if they are moving in the opposite direction ?
36 sec
29 sec.
14 sec
36 sec
Explanation:
Time taken to meet the first time = length of track/relative speed
= 400/ (15 +25) (5/18)
= 400/40 *(18/5) = 36 sec.
Time taken to meet the first time = length of track/relative speed
= 400/ (15 +25) (5/18)
= 400/40 *(18/5) = 36 sec.
1259.Two persons C & D started traveling from A and B which are 300 km apart, towards B and A respectively at 1.00 p.m. C travels at a constant speed of 30 kmph whereas D doubles his speed every hour. If D reaches A in 4 5/8 hours, at what time did C and D meet each other ?
12 p.m
5:00 p.m
4:30 p.m
4:40 p.m
Explanation:
Let speed of D in first hour = x
D’s speed = x+ 2x+ 4x+ 8x+ 16x*(5/8) = 25x
Given 25x=300 :. X = 12
At the end of four hours C traveled 120 (30 *4) kmph and D traveled 12 + 24+ 48 +96 = 180kmph
They meet each other after 4 hours ie at 5 p.m.
Let speed of D in first hour = x
D’s speed = x+ 2x+ 4x+ 8x+ 16x*(5/8) = 25x
Given 25x=300 :. X = 12
At the end of four hours C traveled 120 (30 *4) kmph and D traveled 12 + 24+ 48 +96 = 180kmph
They meet each other after 4 hours ie at 5 p.m.
1260.Two trains T1 and T2 start simultaneously from two stations X and Y respectively towards each other. If they are 70 km apart both 3 and 6 hours after start, then find the distance between the two stations.
500 km
510 km
210 km
240 km
Explanation:
In first 3 hours T1 travels R km and T2 travels S km.
After 6 hours they traveled R+S+70+ 700
2(R+S ) = R+S +140
R+S = 140
Hence distance between XY is R+S+ 70 = 140 +70 =210 km
In first 3 hours T1 travels R km and T2 travels S km.
After 6 hours they traveled R+S+70+ 700
2(R+S ) = R+S +140
R+S = 140
Hence distance between XY is R+S+ 70 = 140 +70 =210 km
1261.Ajith and Rana walk around a circular course 115 km in circumference, starting together from the same point. If they walk at speed of 4 and 5 kmph respectively, in the same direction, when will they meet ?
220km
180km
after 20 hours
after 115 hours
Explanation:
Rana is the faster person.
He gains 1 km in 1 hour.
So Rana will gain one complete round over
Ajith in 115 hours.
i.e. they will meet after 115 hours.
Rana is the faster person.
He gains 1 km in 1 hour.
So Rana will gain one complete round over
Ajith in 115 hours.
i.e. they will meet after 115 hours.
1262.There are 4 people who has to cross a stretch of 300 km. They normally run at a speed of 10 kmph. One of them has a bike that travels at 50 kmph. The bike first takes one person alone and crosses the stretch while the other two keep running. Then he comes back without wasting time and picks up another person from the way, drives him across the stretch, and does the same for the last person. How long does this whole process take?
after 115 minutes
after 20 minutes
24 hrs
58/3 hrs
Explanation:
Time taken to carry 2nd person = 300/50 = 6 hrs.
Time taken to meet 3rd person =(300-6*10)/(50+10) = 4 hrs
Time taken to carry 3rd person = 4 hours
Time taken to meet 4th person = (300 –140)/60 = 8/3
Total time = 6+4+4+8/3+8/3 = 58/3 hours
Time taken to carry 2nd person = 300/50 = 6 hrs.
Time taken to meet 3rd person =(300-6*10)/(50+10) = 4 hrs
Time taken to carry 3rd person = 4 hours
Time taken to meet 4th person = (300 –140)/60 = 8/3
Total time = 6+4+4+8/3+8/3 = 58/3 hours
1263.Ragav took a bus from home to market, that travels at 40 kmph. While walking back at 4 kmph, halfway through, he suddenly realized he was getting late and he cycled back the remaining distance in 30 kmph. Find the average speed.
52 kmph
20 kmph
6.5 kmph
12.0 kmph
Explanation:
Let the distance be 2x(one way)
Time taken by bus = 2x/40, by walking =x/4, by cycling = x/30 hours
:. Average speed = Total Distance = 4x = 4 *60 = 12.0
Total time x/20 + x/4 + x/30 = 3+15+2
Let the distance be 2x(one way)
Time taken by bus = 2x/40, by walking =x/4, by cycling = x/30 hours
:. Average speed = Total Distance = 4x = 4 *60 = 12.0
Total time x/20 + x/4 + x/30 = 3+15+2
1347.A train covers a distance in 50 min, if it runs at a speed of 48kmph on an average. The
speed at which the train must run to reduce the time of journey to 40min will be.
speed at which the train must run to reduce the time of journey to 40min will be.
45 min
60 min
75 min
None of these
Explanation:
Time = 50/60 hr = 5/6hr
Speed = 48mph
distance = S*T = 48 * 5/6 = 40km
time = 40/60hr = 2/3hr
New speed = 40* 3/2 kmph = 60kmph
Time = 50/60 hr = 5/6hr
Speed = 48mph
distance = S*T = 48 * 5/6 = 40km
time = 40/60hr = 2/3hr
New speed = 40* 3/2 kmph = 60kmph
1349.2 trains starting at the same time from 2 stations 200km apart and going in opposite
direction cross each other at a distance of 110km from one of the stations. What is the
ratio of their speeds?
direction cross each other at a distance of 110km from one of the stations. What is the
ratio of their speeds?
7:03
11:09
18:04
None of these
Explanation:
In same time, they cover 110km & 90 km respectively
so ratio of their speed =110: 90 = 11: 9
In same time, they cover 110km & 90 km respectively
so ratio of their speed =110: 90 = 11: 9
1350.In covering a distance of 30 km, Sachin takes 2 hours more than Rohit. If Sachin
doubles his speed, then he would take 1 hour less than Rohit. Sachin speed is:
doubles his speed, then he would take 1 hour less than Rohit. Sachin speed is:
5 kmph
16 kmph
21 kmph
None of these
Explanation:
Let Sachins speed be X km/hr.
Then, 30/x - 30/2x = 3
6x = 30
x = 5 km/hr.
Let Sachins speed be X km/hr.
Then, 30/x - 30/2x = 3
6x = 30
x = 5 km/hr.
1351.A train 140m long running at 60kmph. In how much time will it pass a platform 260m
long?
long?
5 kmph
16 kmph
21 kmph
None of these
Explanation:
Distance travelled = 140 + 260m = 400m,
Speed = 60 * 5/8 = 50/3m
Time = 400 * 3/50 = 24 Seconds
Distance travelled = 140 + 260m = 400m,
Speed = 60 * 5/8 = 50/3m
Time = 400 * 3/50 = 24 Seconds
1352.The ratio between the Speed of two trains is 7: 8. If the second train runs 440 kms in 4
hours, then the speed of the first train is:
hours, then the speed of the first train is:
47.4 km/hr
57.19 km/hr
68.13 km/hr
None of these
Explanation:
Let the speed of two trains be 7x and 8x km/hr.
Then, 8x = (440/4) = 110
x = (110/8) = 13.75
Speed of first train = (7 x 13.75) km/hr = 96.25 km/hr.
Let the speed of two trains be 7x and 8x km/hr.
Then, 8x = (440/4) = 110
x = (110/8) = 13.75
Speed of first train = (7 x 13.75) km/hr = 96.25 km/hr.
1353.Sachin can cover a distance in 1hr 24min by covering 2/3 of the distance at 4 kmph
and the rest at 5kmph.the total distance is?
and the rest at 5kmph.the total distance is?
5km
6km
7km
8km
Explanation:
Distance = 2/3S
distance=1-2/3S=1/3S
21/15 hr=2/3 S/4 + 1/3s /5
84=14/3S * 3
S= 6km
Distance = 2/3S
distance=1-2/3S=1/3S
21/15 hr=2/3 S/4 + 1/3s /5
84=14/3S * 3
S= 6km
1357.A Train Covers a distance in 50 min ,if it runs at a speed of 48kmph on an average.The
speed at which the train must run to reduce the time of journey to 40min will be.
speed at which the train must run to reduce the time of journey to 40min will be.
18 kmph
60 km ph
30 kmph
50 kmph
Explanation:
Time=50/60 hr=5/6hr
Speed=48mph
distance=S*T=48*5/6=40km
time=40/60hr=2/3hr
New speed = 40* 3/2 kmph= 60kmph
Time=50/60 hr=5/6hr
Speed=48mph
distance=S*T=48*5/6=40km
time=40/60hr=2/3hr
New speed = 40* 3/2 kmph= 60kmph
1360.2 trains starting at the same time from 2 stations 200km apart and going in opposite
direction cross each other at a distance of 110km from one of the stations. what is the
ratio of their speeds.
direction cross each other at a distance of 110km from one of the stations. what is the
ratio of their speeds.
Speed ratio=11:9
Speed ratio=11:13
Speed ratio=8:19
Speed ratio=8:11
Explanation:
In same time ,they cover 110km & 90 km respectively
so ratio of their speed =110:90 = 11:9
In same time ,they cover 110km & 90 km respectively
so ratio of their speed =110:90 = 11:9
1361.Two trains start from A & B and travel towards each other at speed of 50kmph and
60kmph resp. At the time of the meeting the second train has traveled 120km more than
the first.the distance between them.
60kmph resp. At the time of the meeting the second train has traveled 120km more than
the first.the distance between them.
1320 km
1325 km
1250 km
1100 km
Explanation:
Let the distance traveled by the first train be x km
then distance covered by the second train is x + 120km
x/50 = x+120 / 60
x= 600
so the distance between A & B is x + x + 120 = 1320 km
Let the distance traveled by the first train be x km
then distance covered by the second train is x + 120km
x/50 = x+120 / 60
x= 600
so the distance between A & B is x + x + 120 = 1320 km
1367.A train covers a distance in 50 min ,if it runs at a speed of 48kmph on an average.The
speed at which the train must run to reduce the time of journey to 40min will be.
speed at which the train must run to reduce the time of journey to 40min will be.
60kmps
61kmps
70kmps
65kmps
Explanation:
Time=50/60 hr=5/6hr
Speed=48mph
distance=S*T=48*5/6=40km
time=40/60hr=2/3hr
New speed = 40* 3/2 kmph= 60kmph
Time=50/60 hr=5/6hr
Speed=48mph
distance=S*T=48*5/6=40km
time=40/60hr=2/3hr
New speed = 40* 3/2 kmph= 60kmph
1380.A train can travel 50% faster than a car. Both start from point A at the same time and
reach point B 75 kms away from A at the same time. On the way, however, the train
lost about 12.5 minutes while stopping at the stations. The speed of the car is:
reach point B 75 kms away from A at the same time. On the way, however, the train
lost about 12.5 minutes while stopping at the stations. The speed of the car is:
100 kmph
110 kmph
120 kmph
130 kmph
Explanation:
Let speed of the car be x kmph.
Then, speed of the train=(150/100)*x=(3/2)*x kmph
(75/x)-(75/(3/2x))=125/(10*60)
(75/x)-(50/x)=5/24
x = 25 x24/ 5 = 120 kmph.
Let speed of the car be x kmph.
Then, speed of the train=(150/100)*x=(3/2)*x kmph
(75/x)-(75/(3/2x))=125/(10*60)
(75/x)-(50/x)=5/24
x = 25 x24/ 5 = 120 kmph.
1381.Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45
kmph. For how many minutes does the bus stop per hour?
kmph. For how many minutes does the bus stop per hour?
9
10
12
20
Explanation:
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km =
9
x 60
min
54 = 10 min.
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km =
9
x 60
min
54 = 10 min.