44032.Robert is travelling on his cycle and has calculated to reach point A at 2 P.M. if he travels at 10 kmph, he will reach there at 12 noon if he travels at 15 kmph. At what speed must he travel to reach A at 1 P.M.?
8 kmph
11 kmph
12 kmph
14 kmph
Explanation:
Let the distance travelled by x km.
Then,$\dfrac{x}{10}-\dfrac{x}{15}$=2
$\Rightarrow$ 3x - 2x = 60
=> x = 60 km.
Time taken to travel 60 km at 10 km/hr =$\left( \dfrac{60}{10} \right)$hrs=6hrs
So, Robert started 6 hours before 2 P.M. i.e., at 8 A.M.
$\therefore$ Required speed =$\left( \dfrac{60}{5} \right)$kmph
=12kmph
Let the distance travelled by x km.
Then,$\dfrac{x}{10}-\dfrac{x}{15}$=2
$\Rightarrow$ 3x - 2x = 60
=> x = 60 km.
Time taken to travel 60 km at 10 km/hr =$\left( \dfrac{60}{10} \right)$hrs=6hrs
So, Robert started 6 hours before 2 P.M. i.e., at 8 A.M.
$\therefore$ Required speed =$\left( \dfrac{60}{5} \right)$kmph
=12kmph
44033.The ratio between the speeds of two trains is 7 : 8. If the second train runs 400 km in 4 hours, then the speed of the first train is:
70 km/hr
75 km/hr
84 km/hr
87.5 km/hr
Explanation:
Let the speed of two trains be 7x and 8x km/hr.
Then,$ 8x =\left( \dfrac{400}{4}\right)=100$
$\Rightarrow x=\left(\dfrac{100}{8}\right)=12.5$
$\therefore$ Speed of first train = (7 x 12.5) km/hr = 87.5 km/hr.
Let the speed of two trains be 7x and 8x km/hr.
Then,$ 8x =\left( \dfrac{400}{4}\right)=100$
$\Rightarrow x=\left(\dfrac{100}{8}\right)=12.5$
$\therefore$ Speed of first train = (7 x 12.5) km/hr = 87.5 km/hr.
44034.A person crosses a 600 m long street in 5 minutes. What is his speed in km per hour?
3.6
7.2
8.4
10
Explanation:
Speed =$ \left(\dfrac{600}{5\times60}\right)$m/sec.
= 2 m/sec.
Converting m/sec to km/hr
= $\left(2\times\dfrac{18}{5}\right)$km/hr
= 7.2 km/hr.
Speed =$ \left(\dfrac{600}{5\times60}\right)$m/sec.
= 2 m/sec.
Converting m/sec to km/hr
= $\left(2\times\dfrac{18}{5}\right)$km/hr
= 7.2 km/hr.
44036.In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay s speed is:
5 kmph
6 kmph
6.25 kmph
7.5 kmph
Explanation:
Let Abhay s speed be x km/hr.
Then,$\dfrac{30}{x}-\dfrac{30}{2x}$=3
$\Rightarrow $6x = 30
$\Rightarrow$ x = 5 km/hr.
Let Abhay s speed be x km/hr.
Then,$\dfrac{30}{x}-\dfrac{30}{2x}$=3
$\Rightarrow $6x = 30
$\Rightarrow$ x = 5 km/hr.
44039.A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is:
35.55 km/hr
36 km/hr
71.11 km/hr
71 km/hr
Explanation:
Total time taken =$\left( \dfrac{160}{64}+\dfrac{160}{80} \right)hrs.=\dfrac{9}{2}hrs.$
$\therefore$ Average speed =$\left(320 \times \dfrac{2}{9}\right)km/hr$
= 71.11 km/hr.
Total time taken =$\left( \dfrac{160}{64}+\dfrac{160}{80} \right)hrs.=\dfrac{9}{2}hrs.$
$\therefore$ Average speed =$\left(320 \times \dfrac{2}{9}\right)km/hr$
= 71.11 km/hr.
44040.Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
9
10
12
20
Explanation:
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km =$\left(\dfrac{9}{54} \times 60 \right)$min
= 10 min
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km =$\left(\dfrac{9}{54} \times 60 \right)$min
= 10 min
44234. A person travels from A to B at a speed of 40 km/hr and returns by increasing his speed by 50%. What is his average speed for both the trips?
60 km/hr
52 km/hr
56 km/hr
48 km/hr
Explanation:
Speed from A to B =40 km/hr
Speed from B to A =40+20=60 km/hr
Average Speed =2×40×6040+60=48 km/hr
Speed from A to B =40 km/hr
Speed from B to A =40+20=60 km/hr
Average Speed =2×40×6040+60=48 km/hr
44236.A man walking at the rate of 5 km/hr crosses a bridge in 15 minutes. What is the length of the bridge (in metres)?
1250
1220
1350
1320
Explanation:
speed =5 km/hr
time =15 minutes
=1/4 hourLength of the bridge
= Distance travelled by the man in 15 minutes=5×1/4 km
=5×1/4×1000 metre
=1250 metre
speed =5 km/hr
time =15 minutes
=1/4 hourLength of the bridge
= Distance travelled by the man in 15 minutes=5×1/4 km
=5×1/4×1000 metre
=1250 metre
44238.A train is moving at the speed of 80 km/hr. What is its speed in metres per second?
22(2/9) m/s
21 m/s
22 m/s
21(1/2) m/s
Explanation:
speed =80 km/hr =80×5/18 m/s
=40×5/9=200/9=22(2/9) m/s
speed =80 km/hr =80×5/18 m/s
=40×5/9=200/9=22(2/9) m/s
44240. A truck covers a distance of 550 metres in 1 minute whereas a train covers a distance of 33 kms in 45 minutes. What is the ratio of their speed?
2:1
1:2
4:3
3:4
Explanation:
Speed of the truck =550 metres/min
Speed of the train =33/45 km/min=33000/45 metres/min
Speed of the truck : Speed of the train
=550:33000/45=55:3300/45=5:300/45
=1:60/45=1:4/3=3:4
Speed of the truck =550 metres/min
Speed of the train =33/45 km/min=33000/45 metres/min
Speed of the truck : Speed of the train
=550:33000/45=55:3300/45=5:300/45
=1:60/45=1:4/3=3:4