[29 – (–2) {6 – (7 – 3)}] ÷ [3 x {5 + (–3) x (–2)}]
1
–1
0
2
Explanation:
[29 – (–2) {6 – (7 – 3)}] ÷ [3 x {5 + (–3) x (–2)}]
= [29 – (–2) {6 – 4}] ÷ [3 x {5 + 6}]
= [29 – (–2) × 2] ÷ [3 x 11]
= [29 – (–4)] ÷ 33
= [29 + 4] ÷ 33
= 33 ÷ 33
= 1