The base of a right triangle is 8 and hypotenuse is 10. Its area is?
12
80
59
24
Explanation:
$h^2= 10^2-8^2 = 6^2\rightarrow h=6$
$\dfrac{1}{2}\times8\times6 = 24$
The base of a right triangle is 8 and hypotenuse is 10. Its area is?
$h^2= 10^2-8^2 = 6^2\rightarrow h=6$
$\dfrac{1}{2}\times8\times6 = 24$