What is the ratio between perimeters of two squares one having 3 times the diagonal then the other?
4:8
1:4
6:2
3:1
Explanation:
d = 3d d = d
a$\sqrt{2}$ = 3d a$\sqrt{2}$ = d
a = 3d/$\sqrt{2}$ a = d/$\sqrt{2}$ => 3: 1
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