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Find the sum of the squares of first 10 odd natural numbers.

1220
1110
1330
1440
Explanation:


Sum of the squares of first n odd numbers = $\dfrac{n(2n + 1)(2n - 1)}{3}$
Sum of squares of first 10 odd numbers = $\dfrac{10 × (2 × 10 + 1)(2 × 10 - 1)}{3}$
= $\dfrac{10 × 21 × 19}{3}$
= 70 × 19
= 1330


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