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Find the sum of the squares of first 15 even natural numbers.

4120
4960
4190
4020
Explanation:


Sum of the squares of first n even numbers = $\dfrac{2n(n + 1)(2n + 1)}{3}$
Sum of squares of first 15 even numbers = $\dfrac{2 × 15 (15 + 1)(2 × 15 + 1)}{3}$
= $\dfrac{30 × 16 × 31}{3}$
= 4960


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