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Find the sum of the squares of first 45 even natural numbers.

125580
155550
135450
145550
Explanation:


Sum of the squares of first n even numbers = $\dfrac{2n(n + 1)(2n + 1)}{3}$
Sum of squares of first 45 even numbers = $\dfrac{2 × 45 (45 + 1)(2 × 45 + 1)}{3}$
= $\dfrac{90 × 46 × 91}{3}$
= 125580


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