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a, b, b, c, c, c, d, d, d, d, . . . . . . Find the 288th letter of this series.

w
y
z
x
Explanation:

Observe that each letter appeared once, twice, thrice .... They form an arithmetic progression. 1+2+3......

We know that sum of first n natural numbers = n(n+1)2n(n+1)2

So n(n+1)2n(n+1)2 ≤≤ 288

For n = 23, we get 276. So for n = 24, the given series crosses 288.

Ans is X.

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