[6] If x and y are the two digits the number 653xy such that this number is divisible by 80, then x+y is

For Competitive Exams

If x and y are the two digits the number 653xy such that this number is divisible by 80, then x+y is equal to:

Explanation:
Since 653xy is divisible by 2 as well as by 5, so y = 0 Now 653x0 is divisible by 8 so 3x0 is also divisible by 8. By hit and trial x=6 and x+y = 6

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