Sivagami is 2 years elder than Meena. After 6 years the total of their ages will be 7 times of their current age. Then age of Sivagami is :
5 years
4 years
2 Years
7 years
Explanation:
Suppose Sivagami present age as x
therefore Meena’s present age = x-2;
present total = x+x-2 = 2x-2
After 6 years,
Shivagami’s age =x+6
Meena’s age = x-2+6=x+4
sum = x+6+x+4 = 2x +10
According to question ,
2x+10 = 7(2x-2)
2x+10 = 14x-14
12x=24
x=2 age of Sivagami is 2
Suppose Sivagami present age as x
therefore Meena’s present age = x-2;
present total = x+x-2 = 2x-2
After 6 years,
Shivagami’s age =x+6
Meena’s age = x-2+6=x+4
sum = x+6+x+4 = 2x +10
According to question ,
2x+10 = 7(2x-2)
2x+10 = 14x-14
12x=24
x=2 age of Sivagami is 2