A thief steals a car at 2.30pm and drives it at 60kmph. The theft is discovered at 3pm
and the owner sets off in another car at 75kmph when will he overtake the thie
6:00 PM
8:00 PM
9:00 PM
5:00 PM
Explanation:
Let the thief is overtaken x hrs after 2.30pm
distance covered by the thief in x hrs = distance covered by
the owner in x-1/2 hr
60x = 75 ( x- ½)
x= 5/2 hr
thief is overtaken at 2.30 pm + 2 ½ hr = 5 pm
Let the thief is overtaken x hrs after 2.30pm
distance covered by the thief in x hrs = distance covered by
the owner in x-1/2 hr
60x = 75 ( x- ½)
x= 5/2 hr
thief is overtaken at 2.30 pm + 2 ½ hr = 5 pm