A man covers a distance on scooter .had he moved 3kmph faster he would have taken
40 min less. If he had moved 2kmph slower he would have taken 40min more. the
distance is.
20
25
30
40
Explanation:
Let distance = x m
Usual rate = y kmph
x/y – x/y+3 = 40/60 hr
2y(y+3) = 9x (equation 1)
x/y-2 – x/y = 40/60 hr y(y-2) = 3x (equation 2)
divide 1 & 2 equations
by solving we get x = 40
Let distance = x m
Usual rate = y kmph
x/y – x/y+3 = 40/60 hr
2y(y+3) = 9x (equation 1)
x/y-2 – x/y = 40/60 hr y(y-2) = 3x (equation 2)
divide 1 & 2 equations
by solving we get x = 40