For CE transistor amplifier, the audio signal voltage across the collector resistance of 2 kΩ is 4 V. If the current amplification factor of the transistor is 100 and the base resistance is 1 kΩ, then the input signal voltage is
15 mV
10 mV
20 mV
30 mV
Explanation:
Av = $\beta \ \dfrac{R_{out}}{R_{in}}$
Av = 100 × $\dfrac{2kΩ}{1kΩ}$
Av = 200.
Av = $\dfrac{(V_{out})_{AC}}{(V_{in})_{AC}}$
$(V_{in})_{AC} = \dfrac{4}{200}$ = 0.02 = 20 mV
