What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad?
814
820
840
844
Explanation:
Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.
Area of each tile = $(41 \times 41)$ cm2.
$\therefore$ Required number of tiles =$ \left(\dfrac{1517 \times 902}{41 \times 41} \right) $= 814. |