If the sum of three consecutive even numbers is 44 more than the average of these numbers, then the largest of these numbers is?
Let the smallest of these number be x. The other two numbers are (x + 2) and (x + 4).
=> x + (x + 2) + (x + 4) = (X + (X+2) + (x+4)) / 3 + 44
=> 3x + 3 $\times$ (x + 2) + 3 $\times$ (x + 4) = x + (x + 2) + (x + 4) + 132
=> 9x + 18 = 3x + 138
=> 6x = 120
=> x = 20
Therefore, the largest number is 24.
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