Two trains are moving in opposite directions 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:
36
45
48
49
Explanation:
Relative speed = (60+ 90) km/hr
| =$ \left(150 \times\dfrac{5}{18} \right) $m/sec |
| =$ \left(\dfrac{125}{3} \right) $m/sec. |
Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
| Required time =$ \left(2000 \times\dfrac{3}{125} \right) $sec = 48 sec. |