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Standard free energies of formation (in kJ/mol) at 298 K are –237.2, –394.4 and –8.2 for H2O(l), CO2(g) and pentane(g), respectively. The value of Eo
cell
for the pentane–oxygen fuel cell is

2.0968 V
1.0968 V
0.0968 V
1.968 V
Additional Questions

The standard reduction potentials of Zn2+ | Zn, Cu2+ | Cu and Ag+ | Ag are respectively –0.76, 0.34 and 0.8V. The following cells were constructed.

a) Zn | Zn2+ || Cu2+ | Cu

b) Zn | Zn2+ || Ag+ | Ag

c) Cu | Cu2+ || Ag+ | Ag

What is the correct order Eo
cell
of these cells?

Answer

The standard electrode potential is measured by ______.

Answer

Corrosion of iron is essentially an electrochemical phenomenon where the cell reaction are ______.

Answer

A button cell used in watches functions as follows:

Zn(s) + Ag2O(s) + H2O(l) → 2Ag(s) + Zn2+(aq) + 2OH (aq)

If half cell potentials are

Zn2+ (aq) + 2e → Zn(s); E° = –0.76 V

Ag2O(s) + H2O(l) + 2e → 2Ag(s)+ 2OH(aq), E° = 0.34 V

The cell potential will be

Answer

Aluminium displaces hydrogen from dilute HCl whereas silver does not. The E.M.F. of a cell prepared by combining Al/Al+3 and Ag/Ag+ is 2.46 V. The reduction potential of silver electrode is + 0.80 V. The reduction potential of aluminium electrode is:

Answer

The reduction potential values of X, Y and Z are –3.05 V, –0.44 V and –0.83 V respectively. Which of the following order is correct with respect to their reducing property?

Answer

For a cell reaction involving two electrons change, the standard e.m.f. of the cell is found to be 0.295 V at 25°C. The equilibrium constant of the reaction at 25°C is

Answer

When KMnO4 acts as an oxidizing agent and ultimately forms MnO2–
4
, MnO2, Mn2O3 and Mn2+, then the number of electrons transferred in each case is

Answer

What is the time (in sec) required for deposition all the silver present in 125mL of 1 MAgNO3 solution by passing a current of 241.25 amperes? (1F = 96500 coulombs)

Answer

On the basis of the following E° values, the strongest oxidizing agent is:

[Fe(CN)6]4– → [Fe(CN)6]3– + e–1; E° = –0.35 V

Fe2+ → Fe3+ + e–1; E° = –0.77 V

Answer
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