Easy Tutorial
For Competitive Exams

If escape velocity from the earth’s surface is 11.2 km/sec. then escape velocity from a planet of mass same as that of earth but radius one fourth as that of earth is

11.2 km/sec
22.4 km/sec
5.65 km/sec
44.8 km/sec
Additional Questions

If ‘r’ represents the radius of the orbit of a satellite of mass ‘m’ moving round a planet of mass ‘M’, the velocity of the satellite is given by

Answer

When the planet comes nearer the sun moves

Answer

Kepler’s second law regarding constancy of arial velocity of a planet is a consequence of the law of conservation of

Answer

The relation between escape velocity and orbit velocity is

Answer

A geostationary satellite is orbiting the earth at a height of 6R above the surface of the earth, R being the radius of the earth. The time period of another satellite at a height of 2.5 R from the surface of earth is

Answer

The distance of Neptune and Saturn from the sun are nearly 1013 m and 1012 m respectively. Assuming that they move in circular orbits, their periodic times would be in the ratio of

Answer

Imagine a light planet revolving around a very massive star in a circular orbit of radius R with a period of revolution T. If the gravitational force of attraction between the planet and the star is proportional to R-5/2 then

Answer

The acceleration due to gravity g and mean density of the earth ρ are related by which of
the following relation? Where g is gravitational constant and R is radius of the earth

Answer

If the earth is 1/4th of its present distance from the sun, the duration of the year would be

Answer

A planet has twice the radius but the mean density is 1/4th as compared to earth. What is the radio of the escape velocity from the earth to that from the planet?

Answer
Share with Friends
Privacy Copyright Contact Us