On dividing 2272 as well as 875 by 3-digit number N, we get the same remainder. The sum of the digits of N is:
10
11
12
13
Explanation:
Clearly, (2272 - 875) = 1397, is exactly divisible by N.
Now, 1397 = 11 x 127
$\therefore$ The required 3-digit number is 127, the sum of whose digits is 10.