Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
39, 30
41, 32
42, 33
43, 34
Explanation:
Let their marks be $\left( x + 9\right)$ and $ x $.
Then, $ x $ + 9 =$ \dfrac{56}{100}$ $\left( x + 9 + x \right)$
$\Rightarrow$ 25$\left( x + 9\right)$ = 14$\left(2 x + 9\right)$
$\Rightarrow$ 3$ x $ = 99
$\Rightarrow x $ = 33
So, their marks are 42 and 33.