Two dice are thrown simultaneously. What is the probability of getting two numbers whose product is even?
$ \dfrac{1}{2} $
$ \dfrac{3}{4} $
$ \dfrac{3}{8} $
$ \dfrac{5}{16} $
Explanation:
In a simultaneous throw of two dice, we have $ n \left(S\right)$ = $(6 \times 6)$ = 36.
Then, E= {(1, 2), (1, 4), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 2), (3, 4),
(3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 2), (5, 4), (5, 6), (6, 1),
(6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}
$\therefore n \left(E\right)$ = 27.
$\therefore P\left(E\right)$ =$ \dfrac{n(E)}{n(S)} $=$ \dfrac{27}{36} $=$ \dfrac{3}{4} $.