A bag contains 6 black and 8 white balls. One ball is drawn at random. What is the probability that the ball drawn is white?
$ \dfrac{3}{4} $
$ \dfrac{4}{7} $
$ \dfrac{1}{8} $
$ \dfrac{3}{7} $
Explanation:
Let number of balls = (6 + 8) = 14.
Number of white balls = 8.
P [drawing a white ball] =$ \dfrac{8}{14} $=$ \dfrac{4}{7} $.