Easy Tutorial
For Competitive Exams

What is the probability of getting a sum 9 from two throws of a dice?

$ \dfrac{1}{6} $
$ \dfrac{1}{8} $
$ \dfrac{1}{9} $
$ \dfrac{1}{12} $
Explanation:

In two throws of a dice, $ n \left(S\right)$ = $(6 \times 6)$ = 36.

Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}.

$\therefore P\left(E\right)$ =$ \dfrac{n(E)}{n(S)} $=$ \dfrac{4}{36} $=$ \dfrac{1}{9} $.

Share with Friends
Privacy Copyright Contact Us