Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronits age. After further 8 years, how many times would he be of Ronits age?
2 times
2 $ \dfrac{1}{2} $times
2 $ \dfrac{3}{4} $times
3 times
Explanation:
Let Ronits present age be $ x $ years. Then, fathers present age =$\left(x+ 3x\right)$ years = 4$ x $ years.
| $\therefore$ $\left(4x+ 8\right)$ =$ \dfrac{5}{2}\left(x+ 8\right)$ |
$\Rightarrow$ 8$ x $ + 16 = 5$ x $ + 40
$\Rightarrow$ 3$ x $ = 24
$\Rightarrow x $ = 8.
| Hence, required ratio =$ \dfrac{(4x + 16)}{(x + 16)} $=$ \dfrac{48}{24} $= 2. |