Easy Tutorial
For Competitive Exams

The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is:

1008
1015
1022
1032
Explanation:

Required number = L.C.M. of $\left(12,16, 18, 21, 28\right)$ + 7

   = 1008 + 7

   = 1015

Share with Friends
Privacy Copyright Contact Us