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The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is:

1677
1683
2523
3363
Explanation:

L.C.M. of 5, 6, 7, 8 = 840.

$\therefore$ Required number is of the form 840 k + 3

Least value of $ k $ for which [840$ k $ + 3] is divisible by 9 is $ k $ = 2.

$\therefore$ Required number = $\left(840 \times 2 + 3\right)$ = 1683.

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