If A and B can do a work in 6 days. B and C can do it in 12 days, C and A can do it in 4 days how many days it would take to finish the same work by all the three together?
8 days
4 days
10 days
2 days
Explanation:
Implementing given statement in terms of equations,we get,
A + B=1/6; as both do 1/6 work in 6 days.
similarly, B + C=1/12;
A + C=1/4;
now adding above equations we get,
==>2(A + B +C)=1/6 + 1/12+1/4;
==>2(A + B +C)=(2+1+3)/12; as, lcm= 12,
==>2(A + B +C)=6/12;
==>(A + B +C)=6/24;
==>(A + B +C)=1/4;
hence they all work in 4 days to complete
Implementing given statement in terms of equations,we get,
A + B=1/6; as both do 1/6 work in 6 days.
similarly, B + C=1/12;
A + C=1/4;
now adding above equations we get,
==>2(A + B +C)=1/6 + 1/12+1/4;
==>2(A + B +C)=(2+1+3)/12; as, lcm= 12,
==>2(A + B +C)=6/12;
==>(A + B +C)=6/24;
==>(A + B +C)=1/4;
hence they all work in 4 days to complete
