$\dfrac{\log\sqrt{8}}{log 8}$ is equal to
$\dfrac{1}{\sqrt{8}}$
$\dfrac{1}{4}$
$\dfrac{1}{2}$
$\dfrac{1}{8}$
Explanation:
$\dfrac{\log\sqrt{8}}{log 8}$
=>$\dfrac{log8{\dfrac{1}{2}}}{log 8}$
=$\dfrac{\dfrac{1}{2}log8}{log 8}$
=$\dfrac{1}{2}$
$\dfrac{\log\sqrt{8}}{log 8}$
=>$\dfrac{log8{\dfrac{1}{2}}}{log 8}$
=$\dfrac{\dfrac{1}{2}log8}{log 8}$
=$\dfrac{1}{2}$