For this find the day of 1.8.1947
number of odd days for 1600 years=0
number of odd days for 300 years=1
From 1991 to 1946, there are 11 leap years + 35 ordinary years.
So, number of odd days = 11 x 2 + 35 x 1=22+35=57=8weeks+1 odd days=1 odd day
Number of days according to the months are
January = 31 days=3 odd days
February = 28 days=0 odd day
March = 31 days=3 odd days
April = 30 days=2odd days
May = 31 days=3odd days
June = 30 days=2odd days
July =31 days=3odd days
August=1 day
Therefore, 3 + 0+ 3 + 2 + 3 + 2+3+1 =17=2 weeks+3 odd days
Total number of odd days = 1+1+3=5
So, 1.8.1947 will be Friday.
Now, Friday will be on 1.8.1947, 8.8.1947, 15.8.1947, 22.8.1947