A runs 1 $\dfrac{3}{8}$ times As fast as B. If A gives B a start of 90 m and they reach the goal at the same time. The goal is at a distance of
330 m
440 m
120 m
280 m
Explanation:
Speed of A : Speed of B = $\dfrac{11}{8}$: 1 = 11 : 8
Let Speed of A = 11k
and Speed of B = 8k
Let the distance to the goal = x
Time taken by A = time taken by B
=$\dfrac{Distance\: travelled\:by\: A}{Speed\: of\: A}$=$\dfrac{Distance\: travelled\:by\: B}{Speed\: of\: B}$
= $\dfrac{x}{11k}$= $\dfrac{x-90}{8k}$
= $\dfrac{x}{11}$= $\dfrac{x-90}{8}$
8x=11x-990
3x=990
x=330
Distance to the goal = 330 metre