The value of - $\sqrt{609+\sqrt{248+\sqrt{60+\sqrt{7+\sqrt{81}}}}}$
20
25
16
9
Explanation:
solve it from right to left=$\sqrt{81}=9 then add with \sqrt{7}=>we get,\sqrt{9+7}=>\sqrt{16}$=4
then $\sqrt{4+60}=>\sqrt{64}=8$
then $\sqrt{8+248}=\sqrt{256}=16$
then $\sqrt{16+609}=\sqrt{625}=25$
solve it from right to left=$\sqrt{81}=9 then add with \sqrt{7}=>we get,\sqrt{9+7}=>\sqrt{16}$=4
then $\sqrt{4+60}=>\sqrt{64}=8$
then $\sqrt{8+248}=\sqrt{256}=16$
then $\sqrt{16+609}=\sqrt{625}=25$