The value of $16^{3}\div 7^{3}$–$23^{3}$ is
-7728
7028
7728
-7718
Explanation:
$16^{3}+7^{3}-23^{3}$ is in the format of=$a^{3}+b^{3}-c^{3}$
then first take$ a^{3}+b^{3}=>16^{3}+7^{3}$ $[(a+b)(a^{2}-ab+b^{2})]$
$=>(16+7)(16^{2}-16(7)+7^{2})$
$=>23(256-112+49)$
=>23(144+49)
=>23(193)
=>4439
$7^{3}$=12167
$16^{3}+7^{3}-23^{3}$=4439-12167=-7728
$16^{3}+7^{3}-23^{3}$ is in the format of=$a^{3}+b^{3}-c^{3}$
then first take$ a^{3}+b^{3}=>16^{3}+7^{3}$ $[(a+b)(a^{2}-ab+b^{2})]$
$=>(16+7)(16^{2}-16(7)+7^{2})$
$=>23(256-112+49)$
=>23(144+49)
=>23(193)
=>4439
$7^{3}$=12167
$16^{3}+7^{3}-23^{3}$=4439-12167=-7728