Three angles of a triangle are x - 30°, x - 45°, x + 15°, find the value of x.
Ꮾ0°
40°
80°
100°
Explanation:
Sum of the angles of triangle=$180^{0}$
therefore,x-30+x-45+x+15=$180^{0}$
3x-60=$180^{0}$
3x=$240^{0}$
x=$240^{0}$/3
x=$80^{0}$
Sum of the angles of triangle=$180^{0}$
therefore,x-30+x-45+x+15=$180^{0}$
3x-60=$180^{0}$
3x=$240^{0}$
x=$240^{0}$/3
x=$80^{0}$