Find the rate of interest at which, a sum of money becomes $\dfrac{9}{4}$ times in 2 years.
69$\frac{1}{2}$%
67$\frac{1}{2}$%
62$\frac{1}{2}$%
61$\frac{1}{2}$%
Explanation:
Principal = P
Amount = $\dfrac{9p}{4}$
S.I. =$\dfrac{9p}{4}-P$
=$\dfrac{9p-4p}{4}$
=$\dfrac{5p}{4}$
Formula R=$\dfrac{(S.I×100)}{(P×T)}$
=$\dfrac{(5 \times p \times 100)}{(4×p×2)}$
= $\dfrac{125}{2}$
=62 $\dfrac {1}{2}$%
Principal = P
Amount = $\dfrac{9p}{4}$
S.I. =$\dfrac{9p}{4}-P$
=$\dfrac{9p-4p}{4}$
=$\dfrac{5p}{4}$
Formula R=$\dfrac{(S.I×100)}{(P×T)}$
=$\dfrac{(5 \times p \times 100)}{(4×p×2)}$
= $\dfrac{125}{2}$
=62 $\dfrac {1}{2}$%