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SSC CGL Tier1 Quantitative Aptitude Time and Work Test 3

1333.Five bells begin to toll together and toll
respectively at intervals of 6,7,8,9 and 12 seconds.
How many times they will toll together
in one hour, excluding the one at the start?
6
7
5
2
Explanation:

L.C.M. of 6,7,8,9 and 12
= 2x2x3x7x2x3 = 504
ie, The bells will toll together after each 504
seconds. In one hour, they will toll together
(60*60)/504= 7 times
1382.If 9 men working 6 hours a day can do a work in 88 days. Then 6 men
working 8 hours a day can do it in how many days?
100days
58days
99days
90days
Explanation:

From the above formula i.e (m1*t1/w1) = (m2*t2/w2)
so (9*6*88/1) = (6*8*d/1)
on solving, d = 99 days.
1383.If 34 men completed 2/5th of a work in 8 days working 9 hours a day.
How many more man should be engaged to finish the rest of the work in 6 days
working 9 hours a day?
100mens
102mens
112mens
120mens
Explanation:
From the above formula i.e (m1*t1/w1) = (m2*t2/w2)
so, (34*8*9/(2/5)) = (x*6*9/(3/5))
so, x = 136 men
number of men to be added to finish the work = 136-34 = 102 men
1384.If 5 women or 8 girls can do a work in 84 days. In how many days can
10 women and 5 girls can do the same work?
30days
32days
35days
40days
Explanation:

Given that 5 women is equal to 8 girls to complete a work. So, 10 women =
16 girls. Therefore 10 women + 5 girls = 16 girls + 5 girls = 21 girls.
8 girls can do a work in 84 days then 21 girls can do a work in (8*84/21) = 32 days.
Therefore 10 women and 5 girls can a work in 32 days
1385.Worker A takes 8 hours to do a job. Worker B takes 10 hours to do the
same job. How long it take both A & B, working together but independently, to do
the same job?
40/9days
39/5days
51/9days
None of these
Explanation:

As one hour work = 1/8. Bs one hour work = 1/10. (A+B)s one hour work
= 1/8+1/10 = 9/40. Both A & B can finish the work in 40/9 days
1386.A can finish a work in 18 days and B can do the same work in half the
time taken by A. Then,working together, what part of the same work they can finish
in a day?
A+B=1/6
A+B=5/6
A+B=1/4
A+B=2/3
Explanation:

Given that B alone can complete the same work in days = half the time
taken by A = 9 days
As one day work = 1/18
Bs one day work = 1/9
(A+B)s one day work = 1/18+1/9 = 1/6

1387.A is twice as good a workman as B and together they finish a piece of
work in 18 days.In how many days will A alone finish the work.
21days
25days
22days
27days
Explanation:

if A takes x days to do a work then B takes 2x days to do the same work
= > 1/x+1/2x = 1/18
= > 3/2x = 1/18
= > x = 27 days.
Hence, A alone can finish the work in 27 days.
1388.A can do a certain work in 12 days. B is 60% more efficient than A.
How many days does B alone take to do the same job?
9/11days
11/7days
15/2days
13/5days
Explanation:

Ratio of time taken by A & B = 160:100 = 8:5
Suppose B alone takes x days to do the job.
Then, 8:5::12:x
= > 8x = 5*12
= > x = 15/2 days.
1389.A can do a piece of work n 7 days of 9 hours each and B alone can do it
in 6 days of 7 hours each. How long will they take to do it working together 8 2/5
hours a day?
2days
3days
4days
None of these
Explanation:

A can complete the work in (7*9) = 63 days
B can complete the work in (6*7) = 42 days
= > As one hours work = 1/63 and
Bs one hour work = 1/42
(A+B)s one hour work = 1/63+1/42 = 5/126
Therefore, Both can finish the work in 126/5 hours.
Number of days of 8 2/5 hours each = (126*5/(5*42)) = 3 days
1390.A takes twice as much time as B or thrice as much time to finish a piece
of work. Working together they can finish the work in 2 days. B can do the work
alone in ?
3hours
6hours
4hours
8hours
Explanation:

Suppose A,B and C take x,x/2 and x/3 hours respectively finish the
work then 1/x+2/x+3/x = 1/2
= > 6/x = 1/2
= >x = 12
So, B takes 6 hours to finish the work.
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