1338.Rohit was 4 times as old as his son 8 years ago. After 8 years, Rohit will be twice as old as
his son. What are their present ages?
his son. What are their present ages?
40
45
42
43
Explanation:
Let sons age 8 years ago be x years. Then, Rohits age 8 years ago = 4x years.
Sons age after 8 years = (x + 8) + 8 = (x + 16) years.
Rohits age after 8 years = (4x + 8) + 8 = (4x+ 16) years.
2 (x + 16) = 4x + 16
2x = 16 => x = 8.
Hence, sons present age = (x + 8) = 16 years.
Rohits present age = (4x + 8) = 40 years
Let sons age 8 years ago be x years. Then, Rohits age 8 years ago = 4x years.
Sons age after 8 years = (x + 8) + 8 = (x + 16) years.
Rohits age after 8 years = (4x + 8) + 8 = (4x+ 16) years.
2 (x + 16) = 4x + 16
2x = 16 => x = 8.
Hence, sons present age = (x + 8) = 16 years.
Rohits present age = (4x + 8) = 40 years
1339.One year ago, the ratio of Gauravs and Sachins age was 6: 7 respectively. Four years
hence, this ratio would become 7: 8. How old is Sa chin ?
hence, this ratio would become 7: 8. How old is Sa chin ?
26 Years
36 Years
40 Years
50 Years
Explanation:
Let Gauravs and Sachins ages one year ago be 6x and 7x years respectively.
Then, Gauravs age 4 years hence = (6x + 1) + 4 = (6x + 5) years.
Sachins age 4 years hence = (7x + 1) + 4 = (7x + 5) years.
(6x+5): (7x + 5) = 7:8
8(6x+5) = 7 (7x + 5)
48x + 40 = 49x + 35
x = 5.
Hence, Sachins present age = (7x + 1) = 36 years.
Let Gauravs and Sachins ages one year ago be 6x and 7x years respectively.
Then, Gauravs age 4 years hence = (6x + 1) + 4 = (6x + 5) years.
Sachins age 4 years hence = (7x + 1) + 4 = (7x + 5) years.
(6x+5): (7x + 5) = 7:8
8(6x+5) = 7 (7x + 5)
48x + 40 = 49x + 35
x = 5.
Hence, Sachins present age = (7x + 1) = 36 years.
1340.The Ratio of Ages of Mona and Sona is 4:5. Twelve Years hence, their ages will be in the
ratio of 5:6. What will be Sonas age after 6 years ?
ratio of 5:6. What will be Sonas age after 6 years ?
40 Years
50 Years
36 Years
66 years
Explanation:
Let their present ages be 4x & 6x
Then (4x + 12)/(5x + 12) = 5/6 or x=12
Sonas age after 6 years = (5x +6) = 66 years
Then (4x + 12)/(5x + 12) = 5/6 or x=12
Sonas age after 6 years = (5x +6) = 66 years
1341.Ramu was 4 times as old as his son 8 years ago. After 8 years, Ramu will be twice as old
as his son. What their present ages ?
as his son. What their present ages ?
36 years
66 years
40 Years
50 Years
Explanation:
Let sons age 8 years ago be x years
Then Ramus age at that time = 4x years
Sons age after 8 years = (x +8) + 8 = (x + 16) years
Ramus age after 8 years = (4x + 8) + 8 = (4x + 16) years
2(x + 16) = 4x + 16 or x=8
Sons present age = (x + 8) = 16 years
Ramus present age= (4x + 8) = 40 years
Let sons age 8 years ago be x years
Then Ramus age at that time = 4x years
Sons age after 8 years = (x +8) + 8 = (x + 16) years
Ramus age after 8 years = (4x + 8) + 8 = (4x + 16) years
2(x + 16) = 4x + 16 or x=8
Sons present age = (x + 8) = 16 years
Ramus present age= (4x + 8) = 40 years
1342.A man is four times as old as his son. Five years ago, the man was nine times as old his
son was at that time. What is the present age of a man ?
son was at that time. What is the present age of a man ?
66 years
40 Years
50 Years
35 years
Explanation:
Let sons age = x, then mans age =4x.
9(x - 5) = (4x-5) or x=8.
Mans present age = (4x + 7) = 35 years
Let sons age = x, then mans age =4x.
9(x - 5) = (4x-5) or x=8.
Mans present age = (4x + 7) = 35 years
1343.The sum of ages of Aruna and her mother is 49 years. Also, 7 years ago, the mothers
age was 4 times Arunas age. Find the present age of Arunas mother.
age was 4 times Arunas age. Find the present age of Arunas mother.
35 years
40 Years
50 Years
30 Years
Explanation:
Let Arunas age 7 years ago be x.
Mothers age 7 years ago = 4x
(x + 7) + (4x + 7) =49 or x=7
Mothers present age = (4x + 7) = 35 years
Let Arunas age 7 years ago be x.
Mothers age 7 years ago = 4x
(x + 7) + (4x + 7) =49 or x=7
Mothers present age = (4x + 7) = 35 years
1344.The ages of A and B differ by 16 years. If 6 years ago, the elder one be 3 times as old as
the younger one, find their present ages.
the younger one, find their present ages.
40 Years
50 Years
30 Years
35 years
Explanation:
Let As age = x & Bs age = (x + 16)
3(x - 6) = (x + 16 - 6) or x=14
As age = 14 years & Bs age = 30 years.
Let As age = x & Bs age = (x + 16)
3(x - 6) = (x + 16 - 6) or x=14
As age = 14 years & Bs age = 30 years.
1345.In three more years, Miguels grandfather will be six times as old as Miguel was last
year. When Miguels present age is added to his grandfathers present age, the total is 68.
How old is each one now?
year. When Miguels present age is added to his grandfathers present age, the total is 68.
How old is each one now?
11 years
12 years
10 years
15 years
Explanation:
Miguels present age be "m"
Grandfathers present age be "g"
Then m + g = 68
Miguels age "last year" was m – 1
His grandfathers age "in three more years" will be g + 3
The grandfathers "age three years from now" is six times Miguels "age last year"
i.e., g + 3 = 6(m – 1)
This gives me two equations with two variables:
m + g = 68
g + 3 = 6(m – 1)
Solving the first equation,
m = 68 – g
g + 3 = 6m – 6
g + 3 = 6(68 – g) – 6
g + 3 = 408 – 6g – 6
g + 3 = 402 – 6g
g + 6g = 402 – 3
7g = 399
g = 57
Since "g" stands for the grandfathers current age, then the grandfather is 57.
Since m + g = 68,
then m = 11
Miguel is presently eleven years old
Miguels present age be "m"
Grandfathers present age be "g"
Then m + g = 68
Miguels age "last year" was m – 1
His grandfathers age "in three more years" will be g + 3
The grandfathers "age three years from now" is six times Miguels "age last year"
i.e., g + 3 = 6(m – 1)
This gives me two equations with two variables:
m + g = 68
g + 3 = 6(m – 1)
Solving the first equation,
m = 68 – g
g + 3 = 6m – 6
g + 3 = 6(68 – g) – 6
g + 3 = 408 – 6g – 6
g + 3 = 402 – 6g
g + 6g = 402 – 3
7g = 399
g = 57
Since "g" stands for the grandfathers current age, then the grandfather is 57.
Since m + g = 68,
then m = 11
Miguel is presently eleven years old
1407.Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively. What is Anands present age in years?
24
27
40
None of these
Explanation:
The present ages fo Sameer and Anand are in the ratio = 5 : 4
Let the present age of Sameer be 5x
Let the present age of Anand be 4x
Given : 3 years after, the ratio of ages = 11 : 9
5x +3 = 11 : 4x +3 = 9
x = 11/9
9 (5x +3 ) = 11 (4x +3 )
45x + 27 = 44x + 33
45x – 44x = 33 – 27
X = 6
To find : Anands Present age (4x = ?)
4 (6) = 24 years
The present ages fo Sameer and Anand are in the ratio = 5 : 4
Let the present age of Sameer be 5x
Let the present age of Anand be 4x
Given : 3 years after, the ratio of ages = 11 : 9
5x +3 = 11 : 4x +3 = 9
x = 11/9
9 (5x +3 ) = 11 (4x +3 )
45x + 27 = 44x + 33
45x – 44x = 33 – 27
X = 6
To find : Anands Present age (4x = ?)
4 (6) = 24 years
2903.Sachins age after 15 years will be 5 times his age 5 years back. Find out the present age of Sachin?
10 years
11 years
12 years
13 years
Explanation:
Let the present age of Sachin = $x$
Then $\left(x + 15\right)$ = 5$\left(x-5\right)$
=> 4$x$ = 40
=> $x$ = 10