[4] The least number of complete years in which a sum of money put out at 20% C.I. will be more than dou

For Competitive Exams

The least number of complete years in which a sum of money put out at 20% C.I. will be more than doubled is :

Explanation:

x(1+20100)n>2xx(1+20100)n>2x or (65)n>2(65)n>2
Now, (65×65×65×65)>2(65×65×65×65)>2
n = 4 years

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