[296+1] It is being given that (232 + 1) is completely divisible by a whole number. Which of the following n

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It is being given that (232 + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number?

216+1

216-1

7x223

296+1

Explanation:

Let 232=x
Then, (232+1)=(x+1)
Let x+1 be completely divisible by natural number N, then
(296+1)=[(232)3+1]=(x3+1)
=(x+1)(x2-x+1), which is completely divisible by N, since (x+1) divisible by N

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