The perimeter of one square is 48 cm and that of another is 20 cm. Find the perimeter and the diagonal of a square which is equal in area to these two combined?
4a = 48
4a = 20
a = 12 a = 5
$a^2$ = 144 $a^2$ = 25
Combined area = $a^2$ = 169 => a = 13
d = 13$\sqrt{2}$
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