The radius of the two circular fields is in the ratio 3: 5 the area of the first field is what percent less than the area of the second?
r = 3 $\pi r^2$ = 9
r = 5 $\pi r^2$ = 25
25 $\pi$ - 16 $\pi$
100 ---- ? => 64%
The radius of the two circular fields is in the ratio 3: 5 the area of the first field is what percent less than the area of the second?
r = 3 $\pi r^2$ = 9
r = 5 $\pi r^2$ = 25
25 $\pi$ - 16 $\pi$
100 ---- ? => 64%
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