[6084] What is the sum of the cubes of first 12 numbers?

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Aptitude

TNPSC G4

10th CBSE Maths

What is the sum of the cubes of first 12 numbers?

6084

4068

8046

8064

Explanation:

Sum of the cubes of first n natural numbers = $\left[\dfrac{n × (n + 1)}{2}\right]^{2}$
Sum of the cubes of first 12 numbers = $\left[\dfrac{12 × (12 + 1)}{2}\right]^{2}$
= $\left[\dfrac{12 × 13}{2}\right]^{2}$
= $(6 × 13)^{2}$
= $78^{2}$
= 6084

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