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If m and n are whole numbers such that $m^n$ = 121, the value of $(m - 1) ^ (n + 1)$ is:

1
10
121
1000
Explanation:

We know that $11^2$ = 121.

Putting m = 11 and n = 2, we get:

$(m - 1)^(n + 1)$ = $(11 - 1) ^ (2 + 1)$ = $10^3$ = 1000.

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