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Find the least number which when divided
separately by 15, 20, 36 and 48 leaves 3 as remainder
in each case.

723
721
720
689
Explanation:

Required number
= L.C.M. of (15,20,36 and 48) +3
= 720 + 3 = 723
Additional Questions

The smallest 3 digit prime number is:

Answer

Which one of the following numbers is exactly divisible by 11?

Answer

(?) - 19657 - 33994 = 9999

Answer

$\dfrac{753 \times 753 + 247 \times 247 - 753 \times 247}{753 \times 753 \times 753 + 247 \times 247 \times 247}$=?

Answer

(?) + 3699 + 1985 - 2047 = 31111

Answer

107 x 107 + 93 x 93 = ?

Answer

How many of the following numbers are divisible by 3 but not by 9 ?
2133, 2343, 3474, 4131, 5286, 5340, 6336, 7347, 8115, 9276

Answer

$\dfrac{(963 + 476)^2 + (963 - 476)^2}{(963 \times 963 + 476 \times 476)}$=?

Answer

8597 - ? = 7429 - 4358

Answer

The smallest prime number is:

Answer
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