Easy Tutorial
For Competitive Exams

A tank is 25 m long, 12 m wide and 6 m deep. The cost of plastering its walls and bottom at 75 paise per sq. m, is:

Rs. 456
Rs. 458
Rs. 558
Rs. 568
Explanation:
Area to be plastered= $[2\left(l + b\right) \times h] $+ $\left(l \times b\right)$

= ${[2\left(25 + 12\right) \times 6] + \left(25 \times 12\right)}$ m2

= (444 + 300) m2

= 744 m2.
$\therefore$ Cost of plastering = Rs.$ \left(744 \times\dfrac{75}{100} \right) $= Rs. 558.
Additional Questions

A rectangular field has to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required?

Answer

An error 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is:

Answer

The breadth of a rectangular field is 60% of its length. If the perimeter of the field is 800 m, find out the area of the field.

Answer

A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required?

Answer

If each side of a square is increased by 25%, find the percentage change in its area?

Answer

Find the area of a square of side 35 m.

Answer

Find the area of a rectangle of length 24 mm and breadth 8 mm.?

Answer

The diameter of a circle is 8 centimeters. What is the area?

Answer

Length of a side of a square field is 275 m. What will be cost of levelling the field at a rate of 10 cent per square metre?

Answer

Find the area of a rectangle whose length is 15 cm and breadth is 50 mm.

Answer
Share with Friends
Privacy Copyright Contact Us