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Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres in what time (in seconds) will they cross each other travelling in opposite direction?

10
12
15
20
Explanation:
Speed of the first train =$ \left(\dfrac{120}{10} \right) $m/sec = 12 m/sec.
Speed of the second train =$ \left(\dfrac{120}{15} \right) $m/sec = 8 m/sec.

Relative speed = (12 + 8) = 20 m/sec.

$\therefore $Required time =[$ \dfrac{(120 + 120)}{20}] $sec = 12 sec.
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