(12 + 22 + 32 + ... + 102) = ?
We know that (12 + 22 + 32 + ... + $ n $2) =$ \dfrac{1}{6} n $$\left( n + 1\right)$$\left(2 n + 1\right)$
Putting $ n $ = 10, required sum =$ \left(\dfrac{1}{6} \times 10 \times 11 \times 21\right) $= 385
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Which one of the following numbers is completely divisible by 99? |
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$\left(51+ 52 + 53 + ... + 100\right)$ = ? |
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1904 x 1904 = ? |
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1 + 2 + 3 + … + 40 = ? |
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What is sum of first 17 natural numbers? |
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Find the sum of first 25 natural numbers. |
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Find the sum of first 100 natural numbers. |
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Find the sum of first 25 even numbers. |
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Find the sum of first 100 even numbers. |
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Find the sum of first 20 odd numbers. |
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