[2.4 hr] Pipe A can fill a tank in 8 hours, pipe B in 4 hours and pipe C in 24 hours. If all the pipes are op

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Pipe A can fill a tank in 8 hours, pipe B in 4 hours and pipe C in 24 hours. If all the pipes are open, in how many hours will the tank be filled?

2.4 hr

3 hr

4 hr

4.2 hr

Explanation:

Part filled by pipe A in 1 hour =$\dfrac{1}{8}$

Part filled by pipe B in 1 hour =$\dfrac{1}{4}$

Part filled by pipe C in 1 hour =$\dfrac{1}{24}$

Part filled by pipes A,B,C together in 1 hour=$\dfrac{1}{8}+\dfrac{1}{4}+\dfrac{1}{24}=\dfrac{10}{24}$

i.e, pipes A,B,C together can fill the tank in $\dfrac{24}{10}$ hour =2.4 hour.

Additional Questions

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Two pipes can fill a tank in 12 minutes and 20 minutes respectively. Both pipes are opened together and after some time the first pipe is closed and the tank is full in totally 10 minutes. For how many minutes was first pipe open?	Answer
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